4y+2x(5y+12)+y^2=0

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Solution for 4y+2x(5y+12)+y^2=0 equation: 


Simplifying
4y + 2x(5y + 12) + y2 = 0

Reorder the terms:
4y + 2x(12 + 5y) + y2 = 0
4y + (12 * 2x + 5y * 2x) + y2 = 0
4y + (24x + 10xy) + y2 = 0

Reorder the terms:
24x + 10xy + 4y + y2 = 0

Solving
24x + 10xy + 4y + y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y' to each side of the equation.
24x + 10xy + 4y + -4y + y2 = 0 + -4y

Combine like terms: 4y + -4y = 0
24x + 10xy + 0 + y2 = 0 + -4y
24x + 10xy + y2 = 0 + -4y
Remove the zero:
24x + 10xy + y2 = -4y

Add '-1y2' to each side of the equation.
24x + 10xy + y2 + -1y2 = -4y + -1y2

Combine like terms: y2 + -1y2 = 0
24x + 10xy + 0 = -4y + -1y2
24x + 10xy = -4y + -1y2

Reorder the terms:
24x + 10xy + 4y + y2 = -4y + 4y + -1y2 + y2

Combine like terms: -4y + 4y = 0
24x + 10xy + 4y + y2 = 0 + -1y2 + y2
24x + 10xy + 4y + y2 = -1y2 + y2

Combine like terms: -1y2 + y2 = 0
24x + 10xy + 4y + y2 = 0

The solution to this equation could not be determined.

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